Unit-2: Thermodynamic Properties of Real Gases
Site: | MSubbu Academy |
Course: | Thermodynamics - Free Course |
Book: | Unit-2: Thermodynamic Properties of Real Gases |
Printed by: | Guest user |
Date: | Friday, 22 November 2024, 11:40 AM |
Table of contents
- Contents
- T-v diagram for the heating process of water at constant pressure
- T-v diagram of contant-pressure phase-change processes
- PVT Diagram of Pure Components
- PT Diagram
- PT Diagram of Water
- PV Diagram
- PV Diagram of Water
- TV Diagram of Water
- Ideal Gas Equation
- van der Waals Equation
- van der Waals Equation
- van der Waals Constants
- Comparison of ideal and van der Waals gas
- Redlich-Kwong Equation
- Peng-Robinson Equation
- Berthelot Equation
- Dieterici Equation
- Example: Trial and Error solution of cubic Equation
- Derivation for a and b of van der Waals
- Example : van der Waals equation - Derivation for a and b in another way van der Waals equation is given as
- Dieterici Equation
- Compressibility Factor
- Virial Equation
- Corresponding State Principle
- Equation of State for a Single Phase
- Equation of State for Liquids
- Quality of Vapor (Dryness Fraction)
- Steam Tables
- Single-phase tables
- Example - Volume from Steam Tables
- Integration Calculations
- Surprise Test
Contents
PVT behaviour of fluids; Mathematical representation of PVT behaviour; Generalized compressibility factor correlation; Generalized equations of state.
T-v diagram for the heating process of water at constant pressure
T-v diagram of contant-pressure phase-change processes
PVT Diagram of Pure Components
The PVT surface above represents a substance which contracts upon freezing. Most substances do so, the notable exception being water, bismuth and antimony which expands upon freezing. The expansion of water upon freezing has an enormous impact on the nature of the Earth.
PT Diagram
Passing from the solid phase directly into the vapor phase is called sublimation.
For substances that have a triple-point pressure above the atmospheric pressure such as solid CO2 (dry ice), sublimation
is the only way to change from the solid to vapor phase at atmospheric conditions.
PT Diagram of Water
Triple
point: P = 611.7 N/m2; T =
0.01oC
Critical point: P= 220.64 x 105 N/m2; T = 374oC
Normal boiling point: 100oC; Normal freezing point: 0oC (1 atm)
PV Diagram
PV Diagram of Water
TV Diagram of Water
Ideal Gas Equation
van der Waals Equation
van der Waals Equation
- The parameter b is related to the size of each molecule. The volume that the molecules have to move around in is not just the volume of the container V, but is reduced to ( V - b )
- The parameter a is related to intermolecular attractive force between the molecules, and 1/V is the density of molecules. The net effect of the intermolecular attractive force is to reduce the pressure for a given volume and temperature.
- When the density of the gas is low (i.e., when 1/V is small and b is small compared to V) the van der Waals equation reduces to that of the ideal gas law.
van der Waals Constants
Substance |
a (J. m3/mole2) |
b (m3/mole) |
Pc (MPa) |
Tc (K) |
Air |
1.1358 |
3.64x10-5 |
3.77 |
133 |
Carbon Dioxide (CO2) |
1.3643 |
4.27x10-5 |
7.39 |
304.2 |
Nitrogen (N2) |
1.1361 |
3.85x10-5 |
3.39 |
126.2 |
Hydrogen (H2) |
1.0247 |
2.65x10-5 |
1.30 |
33.2 |
Water (H2O) |
1.5507 |
3.04x10-5 |
22.09 |
647.3 |
Ammonia (NH3) |
1.4233 |
3.73x10-5 |
11.28 |
406 |
Helium (He) |
1.00341 |
2.34x10-5 |
0.23 |
5.2 |
Freon (CCl2F2) |
1.0780 |
9.98x10-5 |
4.12 |
385 |
Observe that inert gases like Helium have a low value of a as one would expect since such gases do not interact very strongly, and that large molecules like Freon have large values of b.
Comparison of ideal and van der Waals gas
Comparison of actual behavior during isothermal compression to prediction of van der Waals equation.
An
isotherm of the van der Waals equation for T < Tc.
Redlich-Kwong Equation
Peng-Robinson Equation
Berthelot Equation
Dieterici Equation
Example: Trial and Error solution of cubic Equation
Derivation for a and b of van der Waals
Example : van der Waals equation - Derivation for a and b in another way van der Waals equation is given as
Dieterici Equation
Compressibility Factor
Virial Equation
Corresponding State Principle
Equation of State for a Single Phase
Equation of State for Liquids
Quality of Vapor (Dryness Fraction)
Steam Tables
Single-phase tables
Example - Volume from Steam Tables
From the corresponding state principle by
considering Z as a
function of (Tr, Pr)
estimate the volume of 1 kmol of
oxygen at 200 K and 6 x 106
N/m2. (Pc
= 5.05 x 106 N/m2; Tc =
155 K). Z
values for various Tr, Pr are
as given below:
Z |
||||
Tr \( \downarrow \)Pr \( \rightarrow \) | 0.8 |
1.0 |
1.2 |
1.5 |
1.1 |
0.7649 |
0.6880 |
0.5984 |
0.4580 |
1.2 |
0.8330 |
0.7858 |
0.7363 |
0.6605 |
1.3 |
0.8764 |
0.8438 |
0.8111 |
0.7624 |
1.4 |
0.9062 |
0.8827 |
0.8595 |
0.8256 |
1.5 |
0.9278 |
0.9103 |
0.8933 |
0.8689 |
First by considering the interpolation at fixed values of Pr, get Z; then at fixed Tr value get the Z.
That way, you will get Z as 0.807
Integration Calculations
Surprise Test