Unit-2: Thermodynamic Properties of Real Gases
Completion requirements
Example - Volume from Steam Tables
From the corresponding state principle by
considering Z as a
function of (Tr, Pr)
estimate the volume of 1 kmol of
oxygen at 200 K and 6 x 106
N/m2. (Pc
= 5.05 x 106 N/m2; Tc =
155 K). Z
values for various Tr, Pr are
as given below:
Z |
||||
Tr \( \downarrow \)Pr \( \rightarrow \) | 0.8 |
1.0 |
1.2 |
1.5 |
1.1 |
0.7649 |
0.6880 |
0.5984 |
0.4580 |
1.2 |
0.8330 |
0.7858 |
0.7363 |
0.6605 |
1.3 |
0.8764 |
0.8438 |
0.8111 |
0.7624 |
1.4 |
0.9062 |
0.8827 |
0.8595 |
0.8256 |
1.5 |
0.9278 |
0.9103 |
0.8933 |
0.8689 |
First by considering the interpolation at fixed values of Pr, get Z; then at fixed Tr value get the Z.
That way, you will get Z as 0.807